SOLVED: Find the dimensions of B^2/mu0 (B = Magnetic field, mu 0 = magnetic permeability). A. M^1L^-1T^-2 B. M^1L^-1T^-1 C. M^1L^1T^-2 D. M^-1L^-1T^-2
Magnetic Induction
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Magnetic Induction
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![SOLVED: In terms of basic units of mass (M) , length (L) , time (T) and charge (Q) , the dimensions of magnetic permeability of vacuum (mu0) would be A. [MLQ^-2] B. [](https://cdn.numerade.com/previews/e9c82a84-5f43-4c96-a237-3a5cd439295f_large.jpg "SOLVED: In terms of basic units of mass (M) , length (L) , time (T) and charge (Q) , the dimensions of magnetic permeability of vacuum (mu0) would be A. [MLQ^-2] B. [")
SOLVED: In terms of basic units of mass (M) , length (L) , time (T) and charge (Q) , the dimensions of magnetic permeability of vacuum (mu0) would be A. [MLQ^-2] B. [
![Magnetic permeability of vacuum [Encyclopedia Magnetica]](https://e-magnetica.pl/_media/permeabilities_-_magnetica.png "Magnetic permeability of vacuum [Encyclopedia Magnetica]")
Magnetic permeability of vacuum [Encyclopedia Magnetica]
If χ stands for the magnetic susceptibility of a substance, mu for its magnetic permeability and mu0 for the permeability of free space, then
Magnetic Induction
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Relation between the magnetic field vector vec(B) and magnetic intensity vec(H) at a point in a magnetic field vec(B)=muvec(H) where mu is the magnetic permeability of the medium in which the point
